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If cot^2 (x) = cot (x - y) cot(x - z) then show that cot (2x) = 1/2[cot(y) + cot(z)]

If cot^2 (x) = cot (x - y) cot(x - z)
then show that cot (2x) = 1/2[cot(y) + cot(z)]

Grade:11

1 Answers

Lab Bhattacharjee
121 Points
6 years ago
HINT:   use cot(A-B)=[cotB cotA+1]/[\cotB- cotA]

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