If cot^2 (x) = cot (x - y) cot(x - z)then show that cot (2x) = 1/2[cot(y) + cot(z)]
If cot^2 (x) = cot (x - y) cot(x - z)
then show that cot (2x) = 1/2[cot(y) + cot(z)]
Vaibhav Gupta , 10 Years ago
Grade 11
Trigonometry> If cot^2 (x) = cot (x - y) cot(x - z) the...
1 Answers
Lab Bhattacharjee
HINT: use cot(A-B)=[cotB cotA+1]/[\cotB- cotA]
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