MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
If cosecA + secA = cosecB+secB, prove that tanA tanB tan{(A+B)/2} = 1
29 days ago

Answers : (1)

Arun
15903 Points
							
Dear student
 
 
cosecA+secA=cosecB+secB
i.e cosecA-cosecB=secB-secA
=1/sinA-1/sinB=1/cosB-1/cosA
=(sinB-sinA)/sinAsinB=(cosA-cosB)/cosAcosB
=(2sin((B-A)/2)cos((B+A)/2))/sinAsinB=(2sin((B-A)/2)sin((B+A)/2))/cosAcosB
NOTING DOWN THE CONDITION ONLY IF A IS NOT EQUAL TO B CANCEL sin(B-A)/2 from both sides and cross the products to obtain
cos((b+a)/2)/sin((a+b)/2)=sinAsinB/cosAcosB
i.e cot(A+B)/2=tanAtanB
29 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 64 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details