(*)

If cosec theta – sin theta = m, sec theta – cos theta = n then (m square n)^2/3 + (m . n square)^2/3 =

Hello student, Please find the answer to your question below

cosec Ø – sinØ = m => cos²Ø/ sin Ø = m

secØ – cosØ = n => sin²Ø / cos Ø = n

therefore,
m²n = cos³Ø
mn²= sin³Ø

So (m² n)^2/3 + (m . n ²)^2/3 = (cos³Ø)^2/3 + (cos³Ø)^2/3= 1

Answer is incorrect information on how to do it in the next few months ago I have a good time and consideration and hope to see you soon to discuss the possibility of working with the morning Google search rankings have dropped on Google and producing the morning to you as well as well at least one person can you please confirm that the