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# (*)If cosec theta – sin theta = m, sec theta – cos theta = n then (m square n)^2/3 + (m . n square)^2/3 =

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
6 years ago
Hello student, Please find the answer to your question below

cosec Ø – sinØ = m => cos2Ø/ sin Ø = m

secØ – cosØ = n => sin2Ø / cos Ø = n

therefore,
m2n = cos3Ø
mn2= sin3Ø

So (m2 n)^2/3 + (m . n 2)^2/3 = (cos3Ø)^2/3 + (cos3Ø)^2/3= 1
Ayush Kumar
17 Points
3 years ago
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