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If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma than the value of cos (alpha-beta)+cos (beta-gamma)+cos (gamma-alpha)

Seemala Gyaneshwar , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
square both the equations and add them
 
we will get
 
3 + 2 {cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = 0
 
hence
2{cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = – 3
 
{cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = – 3/2
 
 
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