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If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma than the value of cos (alpha-beta)+cos (beta-gamma)+cos (gamma-alpha)

If cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma than the value of cos (alpha-beta)+cos (beta-gamma)+cos (gamma-alpha)
 

Grade:11

1 Answers

Arun
25750 Points
4 years ago
Dear student
 
square both the equations and add them
 
we will get
 
3 + 2 {cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = 0
 
hence
2{cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = – 3
 
{cos( alpha -beta) + cos (beta – gamma) + cos (gamma- alpha)} = – 3/2
 
 

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