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If cos(a-b)+cos(b-c)+cos(c-a)=-3/... then prove that cosa+cosb+cosc=sina+sinb+sinc=0 and hence deduce that cos(a-b)=cos(b-c)=cos(c-a)=-1/2

If cos(a-b)+cos(b-c)+cos(c-a)=-3/... then prove that cosa+cosb+cosc=sina+sinb+sinc=0 and hence deduce that cos(a-b)=cos(b-c)=cos(c-a)=-1/2
 

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
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