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If cos (α+β) = 4/5 and sin (α-β) = 5/13Then tan 2α =?

Shubh Bhinde , 6 Years ago
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Deepak Kumar Shringi

Last Activity: 6 Years ago

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Shubh Bhinde

Last Activity: 6 Years ago

Cos(α+β)=4/5, Tan(α+β)=3/4
Sin(α-β)=5/13, Tan(α-β)=5/12
Tan(2α)= tan[(α+β)+(α-β)]
              =[tan(α+β)+tan(α-β)]/1-tan(α+β)tan(α-β)
              =(3/4 + 5/12)/1-(3/4)(5/12)
              =[(36+20)/48]/[(48-15)/48]
              =56/33

Deepak Kumar Shringi

Last Activity: 6 Years ago

by mistake i have taken tan alpha+beta as ¾ but the method is same

na batau

Last Activity: 6 Years ago

 
Cos(α+β)=4/5, Tan(α+β)=3/4
Sin(α-β)=5/13, Tan(α-β)=5/12
Tan(2α)= tan[(α+β)+(α-β)]
              =[tan(α+β)+tan(α-β)]/1-tan(α+β)tan(α-β)
              =(3/4 + 5/12)/1-(3/4)(5/12)
              =[(36+20)/48]/[(48-15)/48]
              =56/33

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