IF atanA+btanB=(a+b)tan((A+B)/2), a not equal to 0. then prove that:acosB=bcosA

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Saurabh Koranglekar · Answer

https://www.askiitians.com/forums/Trigonometry/23/20123/prove.htm please refer

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IF atanA+btanB=(a+b)tan((A+B)/2), a not equal to 0. then prove that:acosB=bcosA

IF atanA+btanB=(a+b)tan((A+B)/2), a not equal to 0. then prove that:acosB=bcosA

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IF atanA+btanB=(a+b)tan((A+B)/2), a not equal to 0. then prove that:acosB=bcosA

IF atanA+btanB=(a+b)tan((A+B)/2), a not equal to 0. then prove that:acosB=bcosA

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