Grade Select GradeTrigonometry
if ABCD is a quadrilateral then COS(A+B/2)+COS(C+D/2)
if ABCD is a quadrilateral then COS(A+B/2)+COS(C+D/2)
1 Answer
Vijay Mukati
Dear Student, For a quadrilateral, A+B+C+D = 360o. Therefore (C+D)/2 = 180 – (A+B)/2. Put then value in the equation and the result will come out to be zero. Thanks.
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