MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
If ABC.be triangle then acosBcosC+bcosCcosA+ccosAcosB=abc/4R^2 prove it 
11 months ago

Answers : (1)

Aditya Varshney
20 Points
							
 
=cosAcosBcosC[a/cosA + b/cosB + c/cosC]
 
using Sine rule:
=cosAcosBcosC(2R)[tanA + tanB + tanC]
{R= circumradius }
{tanA + tanB + tanC = tanAtanBtanC}
=cosAcosBcosC(2R)sinAsinBsinC/cosAcosBcosC
=2RsinAsinBsinC
 
again using the sine rule
= 2Rabc/2R*2R*2R 
= abc/4R2 
 
where a,b,c = sides of triangle
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details