if a2 Sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )

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Arun · Answer

Dear Alok You have not provided the LHS of part which is to be proved. Please check and respost it. Regards Arun (askIITians forum expert)

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if a2 Sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )

if a2 Sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )

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if a2 Sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )

if a2 Sec 2 θ - b2 tan2 θ =c2 , prove that = ± √(c^2-a^2 )/√(c^2-b^2 )

1 Answers

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