If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)I want solution without assuming theta = 90°
If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)
I want solution without assuming theta = 90°
Gaurav , 3 Years ago
Grade 11
Trigonometry> If A×tan(θ+150°) = B×tan (θ−60°),the valu...
1 Answers
Bharath
Last Activity: 3 Years ago
My dear friend,
I am sorry to you
That I am not able answer your Q
Because the Q which asked I can't
able to understand.
I hope you should get correct answer.
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