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If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B) I want solution without assuming theta = 90°

If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)
I want solution without assuming theta = 90°

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Grade:11

1 Answers

Bharath
90 Points
one year ago
My dear friend, 
I am sorry to you
That I am not able answer your Q
Because the Q which asked I can't 
able to understand. 
I hope you should get correct answer.

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