If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B) I want solution without assuming theta = 90°

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If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B) I want solution without assuming theta = 90°

If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)
I want solution without assuming theta = 90°

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If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B) I want solution without assuming theta = 90°

If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)I want solution without assuming theta = 90°

1 Answers

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If A×tan(θ+150°) = B×tan (θ−60°),the value of (A-B)/(A+B)
I want solution without assuming theta = 90°