If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

Dear Ankita
a² secc² x –b² tan² x = c²
now
a² + a² tan²x – b² tan²x = c²
tan² x = (c² – a²)/ (a² – b²)
tan x =√(c² – a²)/ (a² – b²)
now you can solve all the trigonometric ratio.
Regards
Arun (askIITians forum expert)