If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

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Arun · Answer

Dear Ankita a 2 secc 2 x &ndash;b 2 tan 2 x = c 2 now a 2 + a 2 tan 2 x &ndash; b 2 tan 2 x = c 2 tan 2 x = (c 2 &ndash; a 2 )/ (a 2 &ndash; b 2 ) tan x =&radic;(c 2 &ndash; a 2 )/ (a 2 &ndash; b 2 ) now you can solve all the trigonometric ratio. Regards Arun (askIITians forum expert)

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If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

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If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

If a square*sec square theta - b square tan square theta= c square; prove that; sin theta=+- √c square - a square/ c square-b square

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