If a×sin^2 x+ b×cos^2 x =c ,bsin^2y+a cos^2 y=d and a tanx=b tany then prove that a^2/b^2=d-a/b-c ×c-a/b-d

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sushmitha raj · Answer

R.H.S =d-a/b-c=bsin^2y+acos^2y-1/b-asin^2x-bcos^2x =sin^2y(b-a)/sin^2x(b-a) sin^2y/sin^2x similarly, c-a/b-d=cos^2x/cos^2y (d-a/b-c)(c-a/b-d)=tan^2y/tan^2x L.H.S=a^2/b^2 from,atanx=btany a/b=tany/tanx a^2/b^2=tan^2y/tan^2x Hence,proved REGARDS

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If a×sin^2 x+ b×cos^2 x =c ,bsin^2y+a cos^2 y=d and a tanx=b tany then prove that a^2/b^2=d-a/b-c ×c-a/b-d

If a×sin^2 x+ b×cos^2 x =c ,bsin^2y+a cos^2 y=d and a tanx=b tany then prove that a^2/b^2=d-a/b-c ×c-a/b-d

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If a×sin^2 x+ b×cos^2 x =c ,bsin^2y+a cos^2 y=d and a tanx=b tany then prove that a^2/b^2=d-a/b-c ×c-a/b-d

If a×sin^2 x+ b×cos^2 x =c ,bsin^2y+a cos^2 y=d and a tanx=b tany then prove that a^2/b^2=d-a/b-c ×c-a/b-d

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