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if a=cot inverse (7)+ cot inverse (8)+ cot inverse (18) ,then cot(a)

jerry joseph , 5 Years ago
Grade 12
anser 1 Answers
Varun Kumar

Last Activity: 5 Years ago

Cot inverse A+cot inverse B=cot inverse (AB-1)/A+B
Now
a=cot inverse 7+cot inverse 8+cot inverse 18
 
a=Cot inverse (7*8-1)/(8+7)+cot-inverse 18
a=Cot inverse(11/3)+cot inverse 18
a=cot inverse (11/3*18-1)/(11/3+18)
a=cot inverse (65*3)/65
a=cot inverse (3)
 
Cot a=3
Answer..
 

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