if A=(cosa,sina,0),B=(cosb,sinb,0),C=(cosc,sinc,0) are vertices of triangle abc and cosa+cosb+cosc=3a,sina+sinb+sinc=3b,then orthocentre is

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Saurabh Koranglekar · Answer

Dear student Please attach the image of the question As there is a condition that violets dimension analysis on lhs and rhs of the question, either the part of question is missing or incorrect Regards

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if A=(cosa,sina,0),B=(cosb,sinb,0),C=(cosc,sinc,0) are vertices of triangle abc and cosa+cosb+cosc=3a,sina+sinb+sinc=3b,then orthocentre is

if A=(cosa,sina,0),B=(cosb,sinb,0),C=(cosc,sinc,0) are vertices of triangle abc and cosa+cosb+cosc=3a,sina+sinb+sinc=3b,then orthocentre is

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if A=(cosa,sina,0),B=(cosb,sinb,0),C=(cosc,sinc,0) are vertices of triangle abc and cosa+cosb+cosc=3a,sina+sinb+sinc=3b,then orthocentre is

if A=(cosa,sina,0),B=(cosb,sinb,0),C=(cosc,sinc,0) are vertices of triangle abc and cosa+cosb+cosc=3a,sina+sinb+sinc=3b,then orthocentre is

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