If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively and given that: Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB then prove that the triangle is isosceles

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Himanshu · Answer

Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB > sinA.cosB – cosA.sinB = (a/a+b)sinAcosB-(b/a+b)cosAsinB Comparing both sides. a/a+b = 1 …i) b/a+b = 1 …ii) From i) and ii) , a/a+b = b/a+b a = b Hence, the triangle is isosceles.

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If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively and given that: Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB then prove that the triangle is isosceles

If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively and
given that:
Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB
then prove that the triangle is isosceles

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If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively and given that: Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB then prove that the triangle is isosceles

If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively andgiven that:Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinBthen prove that the triangle is isosceles

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If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively and
given that:
Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB
then prove that the triangle is isosceles