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If a,b,c are the sides of triangle of angle A,B,C,opposite to it respectively andgiven that:Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinBthen prove that the triangle is isosceles

hjh , 8 Years ago
Grade 12
anser 1 Answers
Himanshu

Last Activity: 8 Years ago

Sin(A-B)=(a/a+b)sinAcosB-(b/a+b)cosAsinB
> sinA.cosB – cosA.sinB = (a/a+b)sinAcosB-(b/a+b)cosAsinB
Comparing both sides.
a/a+b = 1          …i)
b/a+b = 1          …ii)
From i) and ii) ,
a/a+b = b/a+b
a = b
Hence, the triangle is isosceles.

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