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if A,B,C are angles of a triangle prove that cosA + cosB + cosC = 1 + r/R if A,B,C are angles of a triangle prove that cosA + cosB + cosC = 1 + r/R
Dear studentUsing the standard result
Dear student CosA + CosB +CosC = 1 + 4 SinA/2 *SinB/2 *SinC/2=> 1+ 4R SinA/2 *SinB/2 *SinC/2=> 1+ r/R Hence prooved
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