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IF A+B+C = 180, THEN (SIN 2A – SIN 2B – SIN 2C) /(SIN 2B – SIN 2A – SIN 2C) =

IF A+B+C = 180, THEN (SIN 2A – SIN 2B – SIN 2C) /(SIN 2B – SIN 2A – SIN 2C) =

Grade:11

1 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
8 years ago
Hello student, Please find the answer to your question below

Sin 2A - Sin 2B – Sin 2C = 4 Cos A Sin B sin C
SIN 2B – SIN 2A – SIN 2C = 4 sinA Sin B cos C

Now you can divide both of them and get answer….….….….….….….….….

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