IF A+B+C=180,prove that (cos A/(sinB sinC)) +( cosB/(sinC sinA)) + (cosC/(sinA sin B))=2

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Arun · Answer

Dear student sin A cosA + sinB cosB + sinc cos C / sinA sinB sinC sin 2A + sin 2B + sin2C / 2 sinA sinB sinC but for a triangle SIn 2A + sin 2B + sin2C = 4 sinA sinB sinC hence its answer will be = 4/2 = 2

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IF A+B+C=180,prove that (cos A/(sinB sinC)) +( cosB/(sinC sinA)) + (cosC/(sinA sin B))=2

IF A+B+C=180,prove that (cos A/(sinB sinC)) +( cosB/(sinC sinA)) + (cosC/(sinA sin B))=2

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IF A+B+C=180,prove that (cos A/(sinB sinC)) +( cosB/(sinC sinA)) + (cosC/(sinA sin B))=2

IF A+B+C=180,prove that (cos A/(sinB sinC)) +( cosB/(sinC sinA)) + (cosC/(sinA sin B))=2

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Other Related Questions on Trigonometry

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