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IF A+B+C=180,FIND THE MINIMUM VALUE OF SIN A+SIN B+SIN C? IF A+B+C=180,FIND THE MINIMUM VALUE OF SIN A+SIN B+SIN C?
Let A=0 B=0 C=180 Hence SIN A+SIN B+SIN C = 0+0+0 hence minimum value for SIN A+ SIN B+SIN C = 0+0+0=0 According to me 0 is the answer.
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