Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If A, B and C are interior angles of a triangle ABC, then show that sin (B+C/2) = cos A/2

If A, B and C are interior angles of a triangle ABC, then show that sin (B+C/2) = cos A/2

Grade:12

1 Answers

Harshit Singh
askIITians Faculty 5964 Points
9 months ago
Dear Student

We know that, for a given triangle,
sum of all the interior angles of a triangle is equal to 180°
A + B + C = 180°....(1)
To find the value of (B+ C)/2, simplify the equation (1)
⇒B + C = 180° - A

⇒(B+C)/2 = (180°-A)/2
⇒(B+C)/2 = (90°-A/2)
Now, multiply both sides by sin functions,
we get
⇒sin (B+C)/2 = sin (90°-A/2)
Since sin (90°-A/2) = cos A/2,
the above equation is equal to
sin (B+C)/2 = cos A/2
Hence proved.

Thanks

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free