COTACOTB)/[(1+COTA)(1+COTB)] = 1/2
TAKING LHS
= (COTACOTB)/[1+COTACOTB +COTA+COTB] ...................1
NOW
COT(A+B)=COTACOTB - 1/COTA+COTB
A+B = 225 (GIVEN)
SO
COT225 = COTACOTB - 1/COTA+COTB
1 = COTACOTB-1/COTA+COTB (COT225=1)
COTA + COTB =COTACOTB - 1 ......................2
PUTTING 2 IN 1 WE GET
LHS= COTACOTB/2COTACOTB
=1/2 = RHS
Regards
Arun (askIITians forum expert)
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