Sunil Raikwar
Last Activity: 11 Years ago
bsec@=c-atan@
squaring both sides
b2sec2@=c2+a2tan2@-2actan@
b2+b2tan2@=c2+a2tan2@-2actan@
(a2-b2)tan2@-2actan@+c2-b2=0
since tana & tanb are the roots of the equation
tana+tanb=2ac/a2-b2, tanatanb=c2-b2/a2-b2
tan(a+b)=tana+tanb/1-tanatab=2ac/a2-b2
Thanks & Ragards
Sunil Raikwar
askIITians Faculty