if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

Question

if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

Saurabh Koranglekar · Answer

please refer https://www.askiitians.com/forums/Trigonometry/if-a-2-7-find-sina-sin2a-sin4a-in-therms-of_148501.htm

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if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

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if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

if a = 2pie/7, then S = (sin a + sin 2a + sin 3a) which can be represent by (root p)/q. Find p+q ?

1 Answers

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