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`        If 4^(sin2x+2cos^2 x) +4^(1-sin2x+2sin^2 x) =65 then sin2x + cos2x has the value equal to`
7 months ago

Deepak Kumar Shringi
4397 Points
```							we can get 65 by 64+1 soeither1-sin2x+2sin2x = 0 or        sin2x+2cos2x=0\                         sin2x+cos2x = -1                          sin(2x+pie/4) = -1                   so 2x+pie/4 =npie+(-1)n 5pie/4 find x from here
```
7 months ago
Anish Singhal
1195 Points
```							If u assume the value of(sin2x+2cos^2 x) as 3 then the factor(1-sin2x+2sin^2 x) will have value 0.Hence by taking value of(sin2x+2cos^2 x) as 3 simplify and find the value of sin2x+cos2x
```
7 months ago
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Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions