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if 3sin0+5cos0=5,then write the value of 5sin0-3cos0=? 0=theta if 3sin0+5cos0=5,then write the value of 5sin0-3cos0=?0=theta
I have assumed theta as x 3sinx +5cosx=5squaring both siods9 sin^2x +25cos^2x+30sinxcosx=259+16cos^2x+30sinxcosx=2516cos^2x+30sinxcosx=1630sinxcosx=16sin^2x30sinxcosx-16sin^2x=0sinx(30cosx-16sinx)=0either sinx =0 or tanx = 15/81) sinx=0cosx=15sinx-3cosx=-32)tanx=15/8sinx=15/17 and cosx =8/175sinx-3cosx=5*15/17-3*8/17=51/17=3
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