Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
if 2tanA=3tanB,prove that tan(A-B)=sin2B/5-cos2B if 2tanA=3tanB,prove that tan(A-B)=sin2B/5-cos2B
Hello student,Given that 2 tan A = 3 tan B,So, tan A = 3/2 tan B ….. (i)
Dear Student,Please find below the solution to your problem.If 2tanA=3tanB or tanA=(3/2).tanBProve that tan(A-B)=sin2B/(5-cos2B)LHS.tan(A-B)=(tanA-tanB)/(1+tanA.tanB), put tanA=(3/2).tanB.=[(3/2)tanB-tanB]/[1+(3/2)tan^2B]=[(1/2).tanB]/[(2cos^2B+3sin^2B)/2cos^2B].=[(sinB/2cosB)×2cos^2B]/[2cos^2B+3sin^2B].=[sinBcosB]/(2cos^2B+3sin^2B)=(sin2B)/2.(2cos^2B+3sin^2B=(sin2B)/(4cos^2B+6sin^2B)=(sin2B)/[4(1-sin^2B)+6sin^2B]=(sin2B)/[4–4sin^2B+6sin^2B]=(sin2B)/[4+2sin^2B) , put 2sin^2B=1-cos2B=(sin2B)/[4+1-cos2B]=(sin2B)/(5-cos2B) , Proved.Thanks and Regards
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -