If 2sin A +3cos A =1 and 2sin B+ 3cos B =1 then the value of cos( A - B ) can be (A)1 (B)0 (C) -11/13 (D) -5/13

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Saurabh Koranglekar · Answer

Dear student Sin A = Sin B A = B + n*( pi ) Cos( B- A) = 1 Regards

Vikas TU · Answer

Dear student Please refer the link below https://www.askiitians.com/iit-jee-mathematics/trigonometry.aspx Good Luck Cheers

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If 2sin A +3cos A =1 and 2sin B+ 3cos B =1 then the value of cos( A - B ) can be (A)1 (B)0 (C) -11/13 (D) -5/13

If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be

(A)1
(B)0
(C) -11/13
(D) -5/13

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If 2sin A +3cos A =1 and 2sin B+ 3cos B =1 then the value of cos( A - B ) can be (A)1 (B)0 (C) -11/13 (D) -5/13

If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be (A)1(B)0(C) -11/13(D) -5/13

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If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be

(A)1
(B)0
(C) -11/13
(D) -5/13