If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be (A)1(B)0(C) -11/13(D) -5/13
If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be
(A)1
(B)0
(C) -11/13
(D) -5/13
Jonathan Jackson , 11 Years ago
Grade 11
Trigonometry> If 2sin A +3cos A =1 and 2sin B+ 3cos B =...
2 Answers
Saurabh Koranglekar
Dear student
Sin A = Sin B
A = B + n*( pi )
Cos( B- A) = 1
Regards
Sin A = Sin B
A = B + n*( pi )
Cos( B- A) = 1
Regards
Vikas TU
Dear student
Please refer the link below
Good Luck
Cheers
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