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If 2sin A +3cos A =1 and 2sin B+ 3cos B =1 then the value of cos( A - B ) can be (A)1 (B)0 (C) -11/13 (D) -5/13

If 2sinA+3cosA=1 and 2sinB+3cosB=1 then the value of cos(A-B) can be 
 
(A)1
(B)0
(C) -11/13
(D) -5/13
 
 

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

Sin A = Sin B

A = B + n*( pi )

Cos( B- A) = 1

Regards
Vikas TU
14149 Points
one year ago
Dear student 
Please refer the link below 
Good Luck 
Cheers

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