Aditya Gupta
Last Activity: 6 Years ago
we see that α+2α+4α=pi/2
taking tan both sides and applying the formula tan(x+y+z)= [tanx+tany+tanz – tanxtanytanz]/[1 – (tanxtany+tanytanz+tanztanx)], we get
[tanα+tan2α+tan4α – tanαtan2αtan4α]/[1 – (tanαtan2α+tan2αtan4α+tanαtan4α)]= not defined.
but this is possible only when the denominator is zero, ie
1 – (tanαtan2α+tan2αtan4α+tanαtan4α)=0
or 1= tanαtan2α+tan2αtan4α+tanαtan4α