If 0≤α,β≤90 degrees and tan⁡(α+β)=3 and tan⁡(α-β)=2,then value of sin2α is?

Hint:
First find the value of tan 2alpha and from here you can easily get the value of sin 2alpha.

Now to find tan 2alpha, we can write tan 2alpha = tan[(alpha + beta)+(alpha-beta)]. Now here apply the formula for tan(A+B) and get its value.

Thanks, Vijay