I didn't understand the part where- 4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)

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Aditya Gupta · Answer

We know that (x+1/x)^2-4= x^2+1/x^2-2= (x-1/x)^2 Also i^2=-1 So that's the way in which the last few manipulations were done.

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I didn't understand the part where- 4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)

I didn't understand the part where-
4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)

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I didn't understand the part where- 4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)

I didn't understand the part where-4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)

1 Answers

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I didn't understand the part where-
4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)