Grade 11Trigonometry
I didn't understand the part where-4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)
I didn't understand the part where-
4sin^2 A= -[(x+1/x)^2 -4] is equal to 4sin^2 A = i^2 [x-1/x)^2] ( the second last step)
