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`        I didn't understand the part where-4sin^2 A= -[(x+1/x)^2 -4]  is equal to 4sin^2 A = i^2 [x-1/x)^2]      ( the second last step)`
one year ago

## Answers : (1)

1808 Points
```							We know that (x+1/x)^2-4= x^2+1/x^2-2= (x-1/x)^2Also i^2=-1So that's the way in which the last few manipulations were done.
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions