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Grade: 11
        
I am unable to find the answer.please solve this............
one year ago

Answers : (1)

sahil
142 Points
							see in triangle Angle A+B+C=180Sol:we are asked cos{(3A+2B+C)÷2}+cos{(A-C)÷2}= cos[{(A-C)÷2}+{(2A+2B+2C)÷2}]+cos{(A-C)÷2} =cos[180+(A-C)÷2]+cos{(A-C)÷2}=-cos{(A-C)÷2}+cos{(A-C)÷2}=0Hence ans is 0I tried my best to give you detail explanation and easy approach.If you are satisfied please click approved.
						
one year ago
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