Grade 11Trigonometry
How the value of f(θ) = sin2 θ + sin2 (θ+2π/3) + sin2 (θ+4π/3) is 3/2?
How the value of f(θ) = sin2 θ + sin2 (θ+2π/3) + sin2 (θ+4π/3) is 3/2?
1 Answer
Arun
Approved Tutor Answer6 Years agoDear student
it can be written as
½ [1- cos 2@ + 1 – cos (2 @ + 4pi/3 ) + 1 – cos ( 2 @ + 8pi/3)]
3/2 – ½ [ cos 2@ – cos(@ + pi/3 ) + cos ( 2pi/3 + 2@)]
Now you can solve
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