how does 4sinA/2.sinB/2.cos(A+B)/2 = – ½ gives A=B=60 degrees ?

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how does 4sinA/2.sinB/2.cos(A+B)/2 = – ½ gives A=B=60 degrees ?

how does 4sinA/2.sinB/2.cos(A+B)/2 = – ½ gives A=B=60 degrees ?

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how does 4sinA/2.sinB/2.cos(A+B)/2 = – ½ gives A=B=60 degrees ?

how does 4sinA/2.sinB/2.cos(A+B)/2 = – ½ gives A=B=60 degrees ?

2 Answers

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