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How do you solve this question? The answer is D..........................
let alpha=r and beta=sin the first eqn put y=sinxso y^2+ay+b=0 has roots sinr and sinsso sinr+sins= –aand sinr*sins= bsimilarly from second eqncosr+coss= –cand coss*cosr= dwe know that sinr+sins= 2sin(r+s)/2*cos(r-s)/2= –acosr+coss = 2cos(r+s)/2*cos(r-s)/2= –cdividetan(r+s)/2= a/clet r+s= 2zso tanz= a/cwe gotta find the value of sin2z= 2tanz/(1+tan^2z)=2ac/(a^2+c^2)
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