Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        How do you solve this question? The answer is D..........................`
11 months ago

1673 Points
```							 let alpha=r and beta=sin the first eqn put y=sinxso y^2+ay+b=0 has roots sinr and sinsso sinr+sins= –aand sinr*sins= bsimilarly from second eqncosr+coss= –cand coss*cosr= dwe know that sinr+sins= 2sin(r+s)/2*cos(r-s)/2= –acosr+coss = 2cos(r+s)/2*cos(r-s)/2= –cdividetan(r+s)/2= a/clet r+s= 2zso tanz= a/cwe gotta find the value of sin2z= 2tanz/(1+tan^2z)=2ac/(a^2+c^2)
```
11 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions