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Help me with the circled ones please. I have a test today. Please open the photo and check out the questions. Thanks! Please respond to me in 1 or 2 hours.


2 years ago

Susmita
425 Points
							ques(ii).write the given eq liketanB+(1-n)tanBtan2A=ntanAor,tanB-ntanA=(n-1)tanBtan2A$Or,tanBtanA=\frac{tanB-ntanA}{(n-1)tanA}$Now $1+tanBtanA=1+\frac{tanB-ntanA}{(n-1)tanA}=\frac{(n-1)tanA+tanB-ntanA}{(n-1)tanA}=\frac{tanA-tanB}{(1-n)tanA}$So $tan(A-B)=\frac{tanA-tanB}{1+tanAtanB}=\frac{(tanA-tanB)(1-n)tanA}{tanA-tanB}=(1-n)tanA$If it helps please approve.

2 years ago
Deepak Kumar Shringi
4404 Points
							dear student. as per forum policy we can answer one question at a time please post one by one

2 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

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