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Help me with the circled ones please. I have a test today. Please open the photo and check out the questions. Thanks! Please respond to me in 1 or 2 hours.

Sahil Sinha , 6 Years ago
Grade 11
anser 2 Answers
Susmita

Last Activity: 6 Years ago

ques(ii).write the given eq like
tanB+(1-n)tanBtan2A=ntanA
or,tanB-ntanA=(n-1)tanBtan2A
Or,tanBtanA=\frac{tanB-ntanA}{(n-1)tanA}
Now 1+tanBtanA=1+\frac{tanB-ntanA}{(n-1)tanA}=\frac{(n-1)tanA+tanB-ntanA}{(n-1)tanA}=\frac{tanA-tanB}{(1-n)tanA}
So tan(A-B)=\frac{tanA-tanB}{1+tanAtanB}=\frac{(tanA-tanB)(1-n)tanA}{tanA-tanB}=(1-n)tanA
If it helps please approve.

Deepak Kumar Shringi

Last Activity: 6 Years ago

dear student.
as per forum policy we can answer one question at a time please post one by one562-1194_Capture.JPG

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