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Grade: 11
        
Help me with the circled ones please. I have a test today. Please open the photo and check out the questions. Thanks! Please respond to me in 1 or 2 hours.
one year ago

Answers : (2)

Susmita
425 Points
							
ques(ii).write the given eq like
tanB+(1-n)tanBtan2A=ntanA
or,tanB-ntanA=(n-1)tanBtan2A
Or,tanBtanA=\frac{tanB-ntanA}{(n-1)tanA}
Now 1+tanBtanA=1+\frac{tanB-ntanA}{(n-1)tanA}=\frac{(n-1)tanA+tanB-ntanA}{(n-1)tanA}=\frac{tanA-tanB}{(1-n)tanA}
So tan(A-B)=\frac{tanA-tanB}{1+tanAtanB}=\frac{(tanA-tanB)(1-n)tanA}{tanA-tanB}=(1-n)tanA
If it helps please approve.
one year ago
Deepak Kumar Shringi
askIITians Faculty
4397 Points
							dear student.
as per forum policy we can answer one question at a time please post one by one562-1194_Capture.JPG
one year ago
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  • Study Planner
  • NCERT Solutions
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  • Previous Year Exam Questions


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