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`        Hello. Help me please. Solve the equation: 3^(sin^2x) +  3^(cos^2x) = 4And find the roots belonging to the gap: [-2pi; -pi/2]Thank you very much.`
10 months ago

Arun
22539 Points
```							Dear student let 3^cos2x = t then 3/t + t= 4 t^2 – 4t + 3= 0 t = 3 or t = 1 hence cos^2 x = 1 or cos^2 x = 0 hence npi/2 points are the roots. so in [pi/2 , – pi/2], roots are pi/2, 0 , – pi/2
```
10 months ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions