Flag Trigonometry> Hello. Help me please. Solve the equation...
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Hello. Help me please.
Solve the equation: 3^(sin^2x) + 3^(cos^2x) = 4
And find the roots belonging to the gap:
[-2pi; -pi/2]
Thank you very much.

Anna Pavlova , 7 Years ago
Grade 11
anser 1 Answers
Arun
Dear student
 
let 3^cos2x = t
 
then
 
3/t + t= 4
 
t^2 – 4t + 3= 0
 
t = 3 or t = 1
 
hence cos^2 x = 1 or cos^2 x = 0
 
hence npi/2 points are the roots.
 
so in [pi/2 , – pi/2], roots are pi/2, 0 , – pi/2
 
Last Activity: 7 Years ago
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