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Given sin2x. Sin3x=sin2x.sin7x prove that x=10 degreePlz answer asap

Given sin2x. Sin3x=sin2x.sin7x prove that x=10 degreePlz answer asap

Grade:11

1 Answers

Spacspade
15 Points
6 years ago
Bringing all terms to the LHS, 
sin2x (sin3x – sin7x) = 0
- 2.(sin2x)^2.cos5x = 0
 
So x is coming out to be = 0 degree or pi/10 ie, 18 degrees. Are you sure you have to prove x=10??                                                                                                                                                                                                                                                                                                                      

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