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Given sin2x. Sin3x=sin2x.sin7x prove that x=10 degreePlz answer asap Given sin2x. Sin3x=sin2x.sin7x prove that x=10 degreePlz answer asap
Bringing all terms to the LHS, sin2x (sin3x – sin7x) = 0- 2.(sin2x)^2.cos5x = 0 So x is coming out to be = 0 degree or pi/10 ie, 18 degrees. Are you sure you have to prove x=10??
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