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Grade 12th passTrigonometry

Give solution to the attached problem

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Profile image of Y RAJYALAKSHMI
12 Years agoGrade 12th pass
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1 Answer

Profile image of Jitender Singh
12 Years ago

Hello student,
Please find answer to your question
y = (cot\alpha )x^{2} + 2(\sqrt{sin\alpha })x + \frac{1}{2}tan\alpha
y < 0, x\in R
\Delta < 0
b^{2}-4ac < 0
b^{2}<4ac
(2\sqrt{sin\alpha })^{2}<4.cot\alpha.\frac{1}{2}tan\alpha
sin\alpha < \frac{1}{2}
\Rightarrow \alpha \in [0, 2\pi ] - [\frac{\pi }{6}, \frac{5\pi }{6}]
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

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