General solution for |sinx|=cosx is....PLEASE ANSWER ASAP!!thanks!
General solution for |sinx|=cosx is....
PLEASE ANSWER ASAP!!thanks!
Shreya , 7 Years ago
Grade 11
Trigonometry> General solution for |sinx|=cosx is.... P...
3 Answers
Arun
Dear Shreya
when sinx >0
sin x = cos x
tanx =1
x = n* pi + pi/4
similarly do this for sinx
Regards
Arun
Approved Last Activity: 7 Years ago
Shreya
Thanks for answering bt I also did it the same way as you did bt the correct answer is 2nΟ + Ο/4 (where n belongs to Integers)...
PLEASE EXPLAIN HOW?
Abhay
As mod us present we have to remove it hence squaring both sides,
Sin2x=cos2x
tan2x = 1
x = npi + pi/4 or npi - pi/4
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