+91-87964 74404
FlagBACK
Question icon
Grade 11Trigonometry

General solution for |sinx|=cosx is....
PLEASE ANSWER ASAP!!thanks!

Profile image of Shreya
8 Years agoGrade 11
Answers icon

3 Answers

Profile image of Arun
ApprovedApproved Tutor Answer8 Years ago
Dear Shreya
 
when sinx >0
 
sin x =  cos x
 
tanx =1
 
x = n* pi + pi/4
 
similarly do this for sinx
 
Regards
Arun
Profile image of Shreya
8 Years ago
Thanks for answering bt I also did it the same way as you did bt the correct answer is 2nπ + π/4 (where n belongs to Integers)...
PLEASE EXPLAIN HOW?
Profile image of Abhay
7 Years ago
As mod us present we have to remove it hence squaring both sides,
Sin2x=cos2x
tan2x = 1
x = npi + pi/4 or npi - pi/4

Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 3 Years ago

question mark
  • Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥 
trigonometry
1 Answer Available

Last Activity: 4 Years ago