Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        For any triangle ABC, prove that b+c/a=cos(B-C/2)/sin (A/2)`
6 months ago

Vikas TU
10470 Points
```							Dear student RHS (b+C)SinA/2 = (kSinB +KSinC )SinA/2 = k(SinB+SinC)SinA/2k+2Sin(B+C)/2 *Cos(B-C)/2 *Sin(A/2) = 2k Sin(pie/2 -A/2)Cos(B-C)/2 SinA/2=> 2KCosA/2 Cos(B-C)/2 SinA/2 = k (2SinA/2CosA/2) Cos(B-C)/2KsinA =a =LHS LHS = RHS
```
6 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Trigonometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions