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Find the value of sin thetha×Cos3thetha×cosec2thetha-2Cos square thetha
Hey I am using A in place of theta.Given sinAcos3Acosec2A-2cos2A I have used only basic formulas to obtain this.If you find any hardle ask me.Hope this helps
Let Theta=¶ Sin¶XCos3¶XCosec2¶-Cos²¶=Sin¶X(4Cos³¶-3Cos¶)X1/sin2¶-Cos²¶=Sin¶X(4Cos³¶-3Cos¶)X1/2sin¶cos¶-Cos²¶=2Cos²¶-3/2-2Cos²¶=-3/2
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