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find the value of Asinx-Bcosx=????? I have a query how we get the value of 1/2sinroot3/2x – root3/2cosroot3/2x = sin(root3/2x-pie/3) please do help

 find the value of Asinx-Bcosx=????? I have a query how we get the value of 
1/2sinroot3/2x – root3/2cosroot3/2x =   
sin(root3/2x-pie/3)
please do help
 

Grade:12th pass

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

There is error in question kindly consider writing standard notation for EQUATION

Kindly repost

Regards

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