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question mark

find the value of Asinx-Bcosx=????? I have a query how we get the value of
1/2sinroot3/2x – root3/2cosroot3/2x =
sin(root3/2x-pie/3)
please do help

MAMTA SRIVASTAVA , 8 Years ago
Grade 12th pass
anser 1 Answers
Saurabh Koranglekar
Dear student

There is error in question kindly consider writing standard notation for EQUATION

Kindly repost

Regards
Last Activity: 6 Years ago
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