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Find the value of angle A in the following equationcos 2A =cos 60°×cos 30° Find the value of angle A in the following equationcos 2A =cos 60°×cos 30°
Cos2A=(√3÷2)×(1÷2)Cos2A= √3÷42CossqureA-1=√3÷42CossqureA=(√3÷4)+1CossqureA=(1÷2)[(√3÷4)+1]CossqureA=(√3÷8)+(1÷2)A=cosinverse[(√3÷8)+(1÷2)]
cos 2A = cos 60°×cos 30° and A= So the concept is of inverse trigonometric .It is so simple ,there is one thing in this question which generally not being asked in exam is the values of cos other than 0, 30,45,60,90
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