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Grade: 11

                        

find the value of 1/cos290+1/(3)^1/2sin 250is equal to

2 years ago

Answers : (1)

Arun
24742 Points
							
cos 290° = cos (270°+20°) = sin 20° 

. . . . . . . . sin 250° = sin (270°-20°) = - cos 20°. 

∴ ( 1 / cos 290° ) + (1 / √3 sin 250° ) 

= ( 1 / sin 20° ) + { 1 / [ √3 ( - cos 20° ) ] } 

= ( √3 cos 20° - sin 20° ) / ( √3 sin 20° cos 20° )

= 2 [ (√3 /2 ) cos 20° - (1/2) sin 20° ] / [ (√3/2) ( 2 sin 40°] 

= 2 ( sin 60° cos 20° - cos 60° sin 20° ) / ((√3/2) sin 40° ) 

= 2 sin (60° - 20°) / ((√3 /2) sin 40° ) 

= 4 / √3 
2 years ago
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