Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
find the value of 1/cos290+1/(3)^1/2sin 250is equal to
cos 290° = cos (270°+20°) = sin 20° . . . . . . . . sin 250° = sin (270°-20°) = - cos 20°. ∴ ( 1 / cos 290° ) + (1 / √3 sin 250° ) = ( 1 / sin 20° ) + { 1 / [ √3 ( - cos 20° ) ] } = ( √3 cos 20° - sin 20° ) / ( √3 sin 20° cos 20° )= 2 [ (√3 /2 ) cos 20° - (1/2) sin 20° ] / [ (√3/2) ( 2 sin 40°] = 2 ( sin 60° cos 20° - cos 60° sin 20° ) / ((√3/2) sin 40° ) = 2 sin (60° - 20°) / ((√3 /2) sin 40° ) = 4 / √3
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -