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Grade: 11
        
find the minimum value of the expression 
1/(cos2(pi/4+x)+sin2(pi/4-x))
2 years ago

Answers : (1)

Shashank Singh
askIITians Faculty
57 Points
							we can write cos^2(pi/4+x)= cos^2(pi/2-(pi/4-x)= sin^2(pi/4-x)
1/(2sin^2(pi/4-x)
the value will be minimum when sin^2(pi/4-x) will be maximum that is
sin^2(pi/4-x)=1
so the minimum value is ½ [ans]
2 years ago
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