Grade 11Trigonometry
find the minimum value of the expression 1/(cos2(pi/4+x)+sin2(pi/4-x))
find the minimum value of the expression
1/(cos2(pi/4+x)+sin2(pi/4-x))
1 Answer
Shashank Singh
we can write cos^2(pi/4+x)= cos^2(pi/2-(pi/4-x)= sin^2(pi/4-x)
1/(2sin^2(pi/4-x)
the value will be minimum when sin^2(pi/4-x) will be maximum that is
sin^2(pi/4-x)=1
so the minimum value is ½ [ans]
1/(2sin^2(pi/4-x)
the value will be minimum when sin^2(pi/4-x) will be maximum that is
sin^2(pi/4-x)=1
so the minimum value is ½ [ans]
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