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Find the general solution of the given equation sin2a=cos3a

Singh , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU
hello mr. singh

given,

 

sin2A=cos3A

 

2 sinA cosA=4cos3A-3cosA

 

2 sin A=4 cos2A-3

 

2 sin A =4(1-sin2A)-3

 

now solve for sinA

 

sin A=(-1-√5)/4  or (-1+√5)/4

 

Put A=18

 

and for 0

 

sin18=(-1+√5)/4

 

 


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Last Activity: 9 Years ago
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