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Grade 12th passTrigonometry

Find the correct answer immediately and get the answer

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Profile image of Naresh
7 Years agoGrade 12th pass
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1 Answer

Profile image of Deepak Kumar Shringi
7 Years ago
MAXIMUM VALUE OF
|sinx|2+|sinx|= 2 so now to get solution minimum b=-2 now when|sinx|2+|sinx| minimum is zero so in that case b=0 in that way b is from [-2,0)